MathDB
A game with binary numbers on board, can we force divisibility?

Source: Dutch TST 2024, 1.3

June 28, 2024
combinatoricscombinatorics proposedgamewinning strategybinary representation

Problem Statement

Player Zero and Player One play a game on a n×nn \times n board (n1n \ge 1). The columns of this n×nn \times n board are numbered 1,2,4,,2n11,2,4,\dots,2^{n-1}. Turn my turn, the players put their own number in one of the free cells (thus Player Zero puts a 00 and Player One puts a 11). Player Zero begins. When the board is filled, the game ends and each row yields a (reverse binary) number obtained by adding the values of the columns with a 11 in that row. For instance, when n=4n=4, a row with 01010101 yields the number 01+12+04+18=100 \cdot1+1 \cdot 2+0 \cdot 4+1 \cdot 8=10.
a) For which natural numbers nn can Player One always ensure that at least one of the row numbers is divisible by 44? b) For which natural numbers nn can Player One always ensure that at least one of the row numbers is divisible by 33?