MathDB
Parallelism

Source: Indian RMO 2000 Problem 5

October 27, 2005
geometrycircumcircleperpendicular bisectorangle bisector

Problem Statement

The internal bisector of angle AA in a triangle ABCABC with AC>ABAC > AB meets the circumcircle Γ\Gamma of the triangle in DD. JoinDD to the center OO of the circle Γ\Gamma and suppose that DODO meets ACAC in EE, possibly when extended. Given that BEBE is perpendicular to ADAD, show that AOAO is parallel to BDBD.