MathDB
TOT 2000 Spring AS1 max of gcd of m + 2000n and n + 2000m

Source:

May 11, 2020
number theorygreatest common divisor

Problem Statement

Positive integers mm and nn have no common divisor greater than one. What is the largest possible value of the greatest common divisor of m+2000nm + 2000n and n+2000mn + 2000m ?
(S Zlobin)