MathDB
geO 98 [convex hexagon ABCDEF with B + D + F = 360°]

Source: IMO Shortlist 1998 Geometry 6

October 1, 2003
trigonometryanalytic geometrygeometryIMO Shortlistcomplex numbers

Problem Statement

Let ABCDEFABCDEF be a convex hexagon such that ∠B+∠D+∠F=360∘\angle B+\angle D+\angle F=360^{\circ } and ABBC⋅CDDE⋅EFFA=1. \frac{AB}{BC} \cdot \frac{CD}{DE} \cdot \frac{EF}{FA} = 1. Prove that BCCA⋅AEEF⋅FDDB=1. \frac{BC}{CA} \cdot \frac{AE}{EF} \cdot \frac{FD}{DB} = 1.
Back to ProblemsView on AoPS