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2011 Kosovo National Mathematical Olympiad
3
KMO #3 (Grade 11) [Maximal value]
KMO #3 (Grade 11) [Maximal value]
Source:
March 13, 2011
function
trigonometry
inequalities
calculus
algebra
system of equations
inequalities proposed
Problem Statement
Find maximal value of the function
f
(
x
)
=
8
−
3
sin
2
(
3
x
)
+
6
sin
(
6
x
)
f(x)=8-3\sin^2 (3x)+6 \sin (6x)
f
(
x
)
=
8
−
3
sin
2
(
3
x
)
+
6
sin
(
6
x
)
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