MathDB
1999 Gauss (7) #1

Source:

July 6, 2011
Gauss

Problem Statement

1999999+991999-999+99 equals
<spanclass=latexbold>(A)</span> 901<spanclass=latexbold>(B)</span> 1099<spanclass=latexbold>(C)</span> 1000<spanclass=latexbold>(D)</span> 199<spanclass=latexbold>(E)</span> 99<span class='latex-bold'>(A)</span>\ 901 \qquad <span class='latex-bold'>(B)</span>\ 1099 \qquad <span class='latex-bold'>(C)</span>\ 1000 \qquad <span class='latex-bold'>(D)</span>\ 199 \qquad <span class='latex-bold'>(E)</span>\ 99