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< IMA = <INB, incenter and arc midpoint of circumcircle related

Source: 2007 Bosnia & Herzegovina JBMO TST p4

May 27, 2020
geometrycircumcircleincenterarc midpointequal angles

Problem Statement

Let II be the incenter of the triangle ABCABC (AB<BCAB < BC). Let MM be the midpoint of ACAC, and let NN be the midpoint of the arc ACAC of the circumcircle of ABCABC which contains BB. Prove that ∠IMA=∠INB\angle IMA = \angle INB.
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