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Weird angle condition results into concurrence

Source: BWM Germany Round 1, 2015 - Problem 3

April 8, 2015
geometryBWMGermanyrayconcurrenceangleTriangle

Problem Statement

Let MM be the midpoint of segment [AB][AB] in triangle ABC\triangle ABC. Let XX and YY be points such that BAX=ACM\angle{BAX}=\angle{ACM} and BYA=MCB\angle{BYA}=\angle{MCB}. Both points, XX and YY, are on the same side as CC with respect to line ABAB. Show that the rays [AX[AX and [BY[BY intersect on line CMCM.