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a,b,c consecutive odd, a^2+b^2+c^2 = 4 equal digits (HOMC 2008 Q7)

Source:

July 25, 2019

number theoryDigits

Problem Statement

Find all triples

(a, b,c)

of consecutive odd positive integers such that

a < b < c

and

a^2 + b^2 + c^2

is a four digit number with all digits equal.