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Danube Competition in Mathematics
2014 Danube Mathematical Competition
1
natural a =(p+q)/r+(q+r)/p+(r+p)/q where p, q,r primes
natural a =(p+q)/r+(q+r)/p+(r+p)/q where p, q,r primes
Source: Danube 2014 junior p1
July 22, 2019
number theory
Sum
primes
natural
Problem Statement
Determine the natural number
a
=
p
+
q
r
+
q
+
r
p
+
r
+
p
q
a =\frac{p+q}{r}+\frac{q+r}{p}+\frac{r+p}{q}
a
=
r
p
+
q
+
p
q
+
r
+
q
r
+
p
where
p
,
q
p, q
p
,
q
and
r
r
r
are prime positive numbers.
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