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dividing a convex 5gon by all its diagonals into 10 triangles and 1 smaller 5gon

Source: 2012 Sharygin Geometry Olympiad Final Round 9.7

August 3, 2018
geometrypentagondiagonalsgeometric inequalityconvex

Problem Statement

A convex pentagon PP is divided by all its diagonals into ten triangles and one smaller pentagon PP'. Let NN be the sum of areas of five triangles adjacent to the sides of PP decreased by the area of PP'. The same operations are performed with the pentagon PP', let NN' be the similar difference calculated for this pentagon. Prove that N>NN > N'.
(A.Belov)