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Old Kyiv MO Geometry
Kyiv City MO 1984-93 - geometry
1990.7.3
angles, a/(b+c)=c/(a+b), 120^o 1990 Kyiv City MO 7.3
angles, a/(b+c)=c/(a+b), 120^o 1990 Kyiv City MO 7.3
Source:
July 18, 2021
geometry
angles
Problem Statement
Given a triangle with sides
a
,
b
,
c
a, b, c
a
,
b
,
c
that satisfy
a
b
+
c
=
c
a
+
b
\frac{a}{b+c}=\frac{c}{a+b}
b
+
c
a
=
a
+
b
c
. Determine the angles of this triangle, if you know that one of them is equal to
12
0
0
120^0
12
0
0
.
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