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BK = 2DC if <ABC =<KAD =<AKD - All-Russian MO 2003 Regional (R4) 8.7

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September 17, 2024
geometryequal segmentsequal angles

Problem Statement

In triangle ABCABC, angle CC is a right angle. Found on the side ACAC point DD, and on the segment BDBD, point KK such that ∠ABC=∠KAD=∠AKD\angle ABC = \angle KAD =\angle AKD. Prove that BK=2DCBK = 2DC.
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