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Triangular Pyramid

Source: 1999 National High School Mathematics League, Exam One, Problem 12

March 10, 2020
geometry3D geometrypyramid

Problem Statement

The bottom surface of triangular pyramid SABCS-ABC is a regular triangle. Projection of AA on plane SBCSBC is HH, which is the orthocenter of SBC\triangle SBC. If HABC=30,SA=23H-AB-C=30^{\circ},SA=2\sqrt3, then the volume of SABCS-ABC is________.