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PEN H Problems
66
H 66
H 66
Source:
May 25, 2007
inequalities
Diophantine Equations
Problem Statement
Let
b
b
b
be a positive integer. Determine all
2002
2002
2002
-tuples of non-negative integers
(
a
1
,
a
2
,
⋯
,
a
2002
)
(a_{1}, a_{2}, \cdots, a_{2002})
(
a
1
,
a
2
,
⋯
,
a
2002
)
satisfying
∑
j
=
1
2002
a
j
a
j
=
2002
b
b
.
\sum^{2002}_{j=1}{a_{j}}^{a_{j}}=2002{b}^{b}.
j
=
1
∑
2002
a
j
a
j
=
2002
b
b
.
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