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1996 Cabri Clubs 1st, finals, 6 problems, Argentinian geo contest

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November 25, 2021
geometryFixed pointconstructioncabri clubsgeometric constructionLocus

Problem Statement

level 1
p1. i. Given three not collinear points A A, B B and CC, find points AA', BB' and C C' on BCBC, ACAC and ABAB, respectively, such that the triangles ABCABC and ABCA'B'C' have the same centroid.
ii. Given three not collinear points A A, B B and CC, find points AA', BB' and C C' on BCBC, ACAC and ABAB, respectively, such that the triangles ABCABC and ABCA'B'C' have the same circumcenter.
p2. Given a parallelogram ABCDABCD, find four points AA', BB', CC' and DD' all interior to the parallelogram such that the triples of points AADAA'D', BBABB'A', CCBCC'B' and DDCDD'C' are collinear and the polygons ADDADD', DCCDC'C, CBBCB'B, AABAA'B and ABCDA'B'C'D' have equal areas.
p3. Construct a circle with center OO. Let ABAB and SJSJ be two perpendicular diameters, in the minor arc BSBS take a variable point HH . For each HH we determine FF, the intersection point between AHAH and SBSB and TT the intersection point between SASA and BHBH. i. Show that TFTF and ABAB are orthogonal. ii. Find the locus of the circumcenter of FSHFSH.
level 2
p4. Given a triangle ABCABC, find the locus of the points P P inside the triangle such that d(P,BC)=d(P,AC)+d(P,AB)d (P,BC) = d (P,AC) + d (P,AB).
Note: d(P,BC)d (P, BC) is the distance from PP from line BCBC.
p5. Construct a circle and take a fixed point AA on it. Draw a variable line r r through AA that is secant to the circle at AA and B B. Construct an isosceles trapezoid ABCDABCD of bases ABAB and CDCD such that AD=DC=1/2ABAD = DC = 1/2 AB. i. Show that line BCBC passes through a fixed point. ii. Find the locus of CC. iii. A line tt perpendicular to ACAC is drawn through DD. Let P P be the intersection point between tt and ABAB. Take JJ on the ray ABAB and XX on the ray PDPD such that AJ=PXAJ = PX. Show that the perpendicular bisector of JXJX passes through the incenter of triangle APDAPD.
p6. Construct a triangle ABCABC, and then find points AA', BB' and C C' on BCBC, ACAC and ABAB, respectively, such that ABA'B' is perpendicular to BCBC, BCB'C' is perpendicular to ACAC and CAC'A' is perpendicular to ABAB.