MathDB
APMO 2017: Bijection between A(n) and B(n)

Source: APMO 2017, problem 3

May 14, 2017
combinatoricsAPMO

Problem Statement

Let A(n)A(n) denote the number of sequences a1a2aka_1\ge a_2\ge\cdots{}\ge a_k of positive integers for which a1++ak=na_1+\cdots{}+a_k = n and each ai+1a_i +1 is a power of two (i=1,2,,k)(i = 1,2,\cdots{},k). Let B(n)B(n) denote the number of sequences b1b2bmb_1\ge b_2\ge \cdots{}\ge b_m of positive integers for which b1++bm=nb_1+\cdots{}+b_m =n and each inequality bj2bj+1b_j\ge 2b_{j+1} holds (j=1,2,,m1)(j=1,2,\cdots{}, m-1). Prove that A(n)=B(n)A(n) = B(n) for every positive integer nn.
Senior Problems Committee of the Australian Mathematical Olympiad Committee