MathDB
$$2(a+b+c)+\frac{9}{(ab+bc+ca)^2}\geq7$$.

Source: 2016 239 S3

October 11, 2020
algebrainequalities

Problem Statement

Positive real numbers aa,bb,cc are given such that abc=1abc=1.Prove that 2(a+b+c)+9(ab+bc+ca)27.2(a+b+c)+\frac{9}{(ab+bc+ca)^2}\geq7.