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Altitude and midpoint circle

Source: Iran MO second round P4

April 19, 2024
geometry

Problem Statement

In the triangle ABCABC, MM is the midpoint of ABAB and BB' is the foot of BB-altitude. CBMCB'M intersects the line BCBC for the second time at DD. Circumcircles of CBMCB'M and ABDABD intersect each other again at KK. The parallel to ABAB through CC intersects the CBMCB'M circle again at LL. Prove that KLKL cuts CMCM in half.