MathDB
pmo problem 8

Source: PMO 2021

March 20, 2021
geometryPMO

Problem Statement

In right triangle ABCABC, ACB=90\angle ACB = 90^{\circ} and tanA>2\tan A > \sqrt{2}. MM is the midpoint of ABAB, PP is the foot of the altitude from CC, and NN is the midpoint of CPCP. Line ABAB meets the circumcircle of CNBCNB again at QQ. RR lies on line BCBC such that QRQR and CPCP are parallel, SS lies on ray CACA past AA such that BR=RSBR = RS, and VV lies on segment SPSP such that AV=VPAV = VP. Line SPSP meets the circumcircle of CPBCPB again at TT. WW lies on ray VAVA past AA such that 2AW=ST2AW = ST, and OO is the circumcenter of SPMSPM. Prove that lines OMOM and BWBW are perpendicular.