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floor(x^2) + ceil(x^2) = 2003

Source: INAMO 2003 - Problem 3

August 5, 2011
floor functionceiling functionalgebra unsolvedalgebra

Problem Statement

Find all real numbers xx such that x2+x2=2003\left\lfloor x^2 \right\rfloor + \left\lceil x^2 \right\rceil = 2003.