MathDB
Prove that BS = BC (chosing the angles) - [ILL 1977]

Source:

January 11, 2011
geometry unsolvedgeometry

Problem Statement

A triangle ABCABC with ∠A=30∘\angle A = 30^\circ and ∠C=54∘\angle C = 54^\circ is given. On BCBC a point DD is chosen such that ∠CAD=12∘. \angle CAD = 12^\circ. On ABAB a point EE is chosen such that ∠ACE=6∘.\angle ACE = 6^\circ. Let SS be the point of intersection of ADAD and CE.CE. Prove that BS=BC.BS = BC.
Back to ProblemsView on AoPS