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tan 2x / tan x - 2 cot 2x / cot x=1

Source: 1962-63 Germany R4 12.2

October 12, 2024
trigonometryalgebra

Problem Statement

For which numbers xxof the interval 0<x<π0 < x <\pi holds: tan⁡2xtan⁡x−2cot⁡2xcot⁡x=1\frac{\tan 2x}{\tan x} -\frac{2 \cot 2x}{\cot x}=1
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