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sum 1/sin 2na = ...

Source: Polish MO Second Round 1964 p1

August 31, 2024
trigonometryalgebra

Problem Statement

Prove that if n n is a natural number and the angle α \alpha is not a multiple of 1802n \frac{180^{\circ}}{2^n} , then 1sin2α+1sin4α+1sin8α+...+=ctgαctg2nα.\frac{1}{\sin 2\alpha} + \frac{1}{\sin 4\alpha} + \frac{1}{\sin 8\alpha} + ... + = ctg \alpha - ctg 2^n \alpha.