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geometric proportion

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February 7, 2016
geometryangle bisector

Problem Statement

In △ABC\triangle ABC the median AMAM is drawn. The foot of perpendicular from BB to the angle bisector of ∠BMA\angle BMA is B1B_1 and the foot of perpendicular from CC to the angle bisector of ∠AMC\angle AMC is C1.C_1. Let MAMA and B1C1B_1C_1 intersect at A1.A_1. Find B1A1A1C1.\frac{B_1A_1}{A_1C_1}.
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