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2024 Poland - Second Round
6
Another vp NT with factorials
Another vp NT with factorials
Source: Polish MO Second round 2024 P6
February 10, 2024
factorial
number theory
Problem Statement
Given is a prime number
p
p
p
. Prove that the number
p
⋅
(
p
2
⋅
p
p
−
1
−
1
p
−
1
)
!
p \cdot (p^2 \cdot \frac{p^{p-1}-1}{p-1})!
p
⋅
(
p
2
⋅
p
−
1
p
p
−
1
−
1
)!
is divisible by
∏
i
=
1
p
(
p
i
)
!
.
\prod_{i=1}^{p}(p^i)!.
i
=
1
∏
p
(
p
i
)!
.
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