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Putnam
1998 Putnam
5
Putnam 1998 B5
Putnam 1998 B5
Source:
April 7, 2012
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Problem Statement
Let
N
N
N
be the positive integer with 1998 decimal digits, all of them 1; that is,
N
=
1111
⋯
11.
N=1111\cdots 11.
N
=
1111
⋯
11.
Find the thousandth digit after the decimal point of
N
\sqrt N
N
.
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