MathDB
probability that the light is on, 5 switches, circuit diagram

Source: Netherlands - Dutch MO 1984 p2

December 25, 2022
combinatoricsprobability

Problem Statement

The circuit diagram drawn (see figure ) contains a battery BB, a lamp LL and five switches S1S_1 to S5S_5. The probability that switch S3S_3 is closed (makes contact) is 23\frac23, for the other four switches that probability is 12\frac12 (the probabilities are mutually independent). Calculate the probability that the light is on.
[asy] unitsize (2 cm);
draw((-1,1)--(-0.5,1)); draw((-0.25,1)--(1,1)--(1,0.25)); draw((1,-0.25)--(1,-1)--(0.05,-1)); draw((-0.05,-1)--(-1,-1)--(-1,0.25)); draw((-1,0.5)--(-1,1)); draw((-1,1)--(-0.5,0.5)); draw((-0.25,0.25)--(0,0)); draw((-1,0)--(-0.75,0)); draw((-0.5,0)--(0,0)); draw((0,1)--(0,0.75)); draw((0,0.5)--(0,0)); draw((-0.25,1)--(-0.5,1.25)); draw((-1,0.25)--(-1.25,0.5)); draw((-0.5,0.5)--(-0.25,0.5)); draw((0,0.75)--(0.25,0.5)); draw((-0.75,0)--(-0.5,-0.25)); draw(Circle((1,0),0.25)); draw(((1,0) + 0.25*dir(45))--((1,0) + 0.25*dir(225))); draw(((1,0) + 0.25*dir(135))--((1,0) + 0.25*dir(315))); draw((0.05,-0.9)--(0.05,-1.1)); draw((-0.05,-0.8)--(-0.05,-1.2));
label("LL", (1.25,0), E); label("BB", (-0.1,-1.1), SW); label("S1S_1", (-0.5,1.25), NE); label("S2S_2", (-1.25,0.5), SW); label("S3S_3", (-0.5,0.5), SW); label("S4S_4", (0.25,0.5), NE); label("S5S_5", (-0.5,-0.25), SW); [/asy]