MathDB
fixed incenter, equilateral, <ABE+< ACF=60^o (2019 Kyiv City MO Round2 9.3)

Source:

September 18, 2020
geometryincenterfixedFixed pointEquilateral

Problem Statement

The equilateral triangle ABCABC is inscribed in the circle ww. Points FF and EE on the sides ABAB and ACAC, respectively, are chosen such that ABE+ACF=60o\angle ABE+ \angle ACF = 60^o. The circumscribed circle of AFE\vartriangle AFE intersects the circle ww at the point DD for the second time. The rays DEDE and DFDF intersect the line BCBC at the points XX and YY, respectively. Prove that the center of the inscribed circle of DXY\vartriangle DXY does not depend on the choice of points FF and EE.
(Hilko Danilo)