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India LIMIT
2019 LIMIT
2019 LIMIT Category B
Problem 11
floor function, size comparison
floor function, size comparison
Source: LIMIT 2019 CBS2 P11
April 28, 2021
algebra
floor function
function
Bounding
Problem Statement
⌊
(
1
⋅
2
+
2
⋅
2
2
+
…
+
100
⋅
2
100
)
⋅
9
−
901
⌋
=
?
\left\lfloor\left(1\cdot2+2\cdot2^2+\ldots+100\cdot2^{100}\right)\cdot9^{-901}\right\rfloor=?
⌊
(
1
⋅
2
+
2
⋅
2
2
+
…
+
100
⋅
2
100
)
⋅
9
−
901
⌋
=
?
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