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\sqrt{x + a} +\sqrt{y+b}+\sqrt{z + c} - All-Russian MO 1997 Regional (R4) 10.8

Source:

September 24, 2024
algebraradical

Problem Statement

Prove that if x+a+y+b+z+c=y+a+z+b+x+c=z+a+x+b+y+c\sqrt{x + a} +\sqrt{y+b}+\sqrt{z + c} =\sqrt{y + a} +\sqrt{z + b} +\sqrt{x + c} =\sqrt{z + a} +\sqrt{x+b}+\sqrt{y+c} for some a,b,c,x,y,za, b, c, x, y, z, then x=y=zx = y = z or a=b=ca = b = c.