MathDB
Weird but easy inequality with absolute values

Source: ARO Regional stage 2023 11.9

February 16, 2023
absolute valuealgebraRussiainequalities proposed

Problem Statement

If a,b,ca, b, c are non-zero reals, prove that babc+cacb+bc+1>1|\frac{b} {a}-\frac{b} {c}|+|\frac{c} {a}-\frac{c}{b}|+|bc+1|>1.