MathDB
Non cyclic inequality

Source: Turkey National Mathematical Olympiad 2020 P3

March 8, 2021
inequalitiesinequalities proposedTurkey

Problem Statement

If x,y,zx, y, z are positive real numbers find the minimum value of 2(x+y+z)(1x+1y+1z)(1+xy)(1+yz)2\sqrt{(x+y+z) \left( \frac{1}{x}+ \frac{1}{y} + \frac{1}{z} \right)} - \sqrt{ \left( 1+ \frac{x}{y} \right) \left( 1+ \frac{y}{z} \right)}