MathDB
Point in the interior

Source: 2019 Second Round - Poland

July 8, 2019
geometrylengthsangles

Problem Statement

Let XX be a point lying in the interior of the acute triangle ABCABC such that \begin{align*} \sphericalangle BAX = 2\sphericalangle XBA \ \ \ \ \hbox{and} \ \ \ \ \sphericalangle XAC = 2\sphericalangle ACX. \end{align*} Denote by MM the midpoint of the arc BCBC of the circumcircle (ABC)(ABC) containing AA. Prove that XM=XAXM=XA.