MathDB
incentre of ABC lies on segment PQ iff AB + AC = 3BC, mixtilinear related

Source: RMM Shortlist 2017 G2

July 4, 2019
geometryincentermixtilinear

Problem Statement

Let ABCABC be a triangle. Consider the circle ωB\omega_B internally tangent to the sides BCBC and BABA, and to the circumcircle of the triangle ABCABC, let PP be the point of contact of the two circles. Similarly, consider the circle ωC\omega_C internally tangent to the sides CBCB and CACA, and to the circumcircle of the triangle ABCABC, let QQ be the point of contact of the two circles. Show that the incentre of the triangle ABCABC lies on the segment PQPQ if and only if AB+AC=3BCAB + AC = 3BC.
proposed by Luis Eduardo Garcia Hernandez, Mexico