MathDB
Making the numbers A,B,C,D from the digits 1,2,3...9 once

Source: Baltic Way 1996 Q17

March 19, 2011
combinatorics proposedcombinatorics

Problem Statement

Using each of the eight digits 1,3,4,5,6,7,81,3,4,5,6,7,8 and 99 exactly once, a three-digit number AA, two two-digit numbers BB and CC, B<CB<C, and a one digit number DD are formed. The numbers are such that A+D=B+C=143A+D=B+C=143. In how many ways can this be done?
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