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diophantine 2^x - y^2 = 4 (HOMC 2017 S Q2)

Source:

September 8, 2019
Diophantine equationdiophantinenumber theory

Problem Statement

How many pairs of positive integers (x,y)(x, y) are there, those satisfy the identity 2xāˆ’y2=42^x - y^2 = 4?
(A): 11 (B): 22 (C): 33 (D): 44 (E): None of the above.
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