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Putnam
1998 Putnam
1
1998 Putnam B1
1998 Putnam B1
Source:
April 19, 2013
Putnam
college contests
Putnam calculus
Problem Statement
Find the minimum value of
(
x
+
1
/
x
)
6
−
(
x
6
+
1
/
x
6
)
−
2
(
x
+
1
/
x
)
3
+
(
x
3
+
1
/
x
3
)
\dfrac{(x+1/x)^6-(x^6+1/x^6)-2}{(x+1/x)^3+(x^3+1/x^3)}
(
x
+
1/
x
)
3
+
(
x
3
+
1/
x
3
)
(
x
+
1/
x
)
6
−
(
x
6
+
1/
x
6
)
−
2
for
x
>
0
x>0
x
>
0
.
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