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Beautiful geometrical inequality

Source: Russian TST 2016, Day 8 P3 (Group NG)

April 19, 2023
geometryInequality

Problem Statement

Prove that for any points A,B,C,DA,B,C,D in the plane, the following inequality holds ABDA+DB+BCDB+DCACDA+DC.\frac{AB}{DA+DB}+\frac{BC}{DB+DC}\geqslant\frac{AC}{DA+DC}.