MathDB
(a+b+c)/2-ab/(a+b)-bc/(b+c)-ca/(c+a)\ge 0, a(1+b)+b(1+c)+c(1+a)\ge 6\sqrt{abc}

Source: Greece JBMO TST 1999

May 25, 2019
inequalitiesthree variable inequalityalgebra

Problem Statement

For a,b,c>0a,b,c>0, prove that (i) a+b+c2aba+bbcb+ccac+a0\frac{a+b+c}{2}-\frac{ab}{a+b}-\frac{bc}{b+c}-\frac{ca}{c+a}\ge 0 (ii) a(1+b)+b(1+c)+c(1+a)6abca(1+b)+b(1+c)+c(1+a)\ge 6\sqrt{abc}