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a_{n+1} = a_n +\tau (n), consective terms are perfect squares

Source: 2012 Balkan Shortlist BMO N1

April 5, 2020
number theorySequencePerfect SquaresconsecutivePerfect Square

Problem Statement

A sequence (an)n=1(a_n)_{n=1}^{\infty} of positive integers satisfies the condition an+1=an+τ(n)a_{n+1} = a_n +\tau (n) for all positive integers nn where τ(n)\tau (n) is the number of positive integer divisors of nn. Determine whether two consecutive terms of this sequence can be perfect squares.