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Vojtěch Jarník IMC
2002 VJIMC
Problem 2
n|2^n-2 for n=(2^(2p)-1)/3
n|2^n-2 for n=(2^(2p)-1)/3
Source: VJIMC 2002 1.2
July 16, 2021
number theory
Divisibility
primes
Problem Statement
Let
p
>
3
p>3
p
>
3
be a prime number and
n
=
2
2
p
−
1
3
n=\frac{2^{2p}-1}3
n
=
3
2
2
p
−
1
. Show that
n
n
n
divides
2
n
−
2
2^n-2
2
n
−
2
.
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