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Ukraine Correspondence MO - geometry
2003.8
angle wanted, CE=BC/3 (2003 VIII All-Ukrainian Correspondence MO 5-11 p8)
angle wanted, CE=BC/3 (2003 VIII All-Ukrainian Correspondence MO 5-11 p8)
Source:
January 10, 2023
geometry
angles
Problem Statement
In the triangle
A
B
C
ABC
A
BC
,
D
D
D
is the midpoint of
A
B
AB
A
B
, and
E
E
E
is the point on the side
B
C
BC
BC
, for which
C
E
=
1
3
B
C
CE = \frac13 BC
CE
=
3
1
BC
. It is known that
∠
A
D
C
=
∠
B
A
E
\angle ADC =\angle BAE
∠
A
D
C
=
∠
B
A
E
. Find
∠
B
A
C
\angle BAC
∠
B
A
C
.
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