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4
66...66x55...55 divisible by 7 (2023 Auckland MO p4)
66...66x55...55 divisible by 7 (2023 Auckland MO p4)
Source:
March 26, 2024
number theory
Problem Statement
Which digit must be substituted instead of the star so that the following large number
66...66
⏟
2023
⋆
55...55
⏟
2023
\underbrace{66...66}_{2023} \star \underbrace{55...55}_{2023}
2023
66...66
⋆
2023
55...55
is divisible by
7
7
7
?
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