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sum of areas of rectangles equals n(n + 2)(7n + 4)/24

Source: 2006 Austria Beginners' Competition p3

October 12, 2022
combinatoricscombinatorial geometry

Problem Statement

Let nn be an even positive integer. We consider rectangles with integer side lengths kk and k+1k +1, where kk is greater than n2\frac{n}{2} and at most equal to nn. Show that for all even positive integers n n the sum of the areas of these rectangles equals n(n+2)(7n+4)24.\frac{n(n + 2)(7n + 4)}{24}.