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1/x + 2/y + 3/z = 1, diophantine, x > y > z

Source: 2006 Bosnia & Herzegovina JBMO TST p1

May 27, 2020
number theorydiophantineDiophantine equation

Problem Statement

. Find all triplets (x,y,z)(x, y, z), x>y>zx > y > z of positive integers such that 1x+2y+3z=1\frac{1}{x}+\frac{2}{y}+\frac{3}{z}= 1
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