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Regional Olympiad - FBH 2010 Grade 10 Problem 2

Source: Regional Olympiad - Federation of Bosnia and Herzegovina 2010

September 27, 2018
geometryidentity

Problem Statement

It is given acute triangle ABCABC with orthocenter at point HH. Prove that AHha+BHhb+CHhc=a2+b2+c22AH \cdot h_a+BH \cdot h_b+CH \cdot h_c=\frac{a^2+b^2+c^2}{2} where aa, bb and cc are sides of a triangle, and hah_a, hbh_b and hch_c altitudes of ABCABC