MathDB
Inequality with abc=1

Source: JBMO 2011 Shortlist A7

May 15, 2016
inequalitiesHi

Problem Statement

A7\boxed{\text{A7}} Let a,b,ca,b,c be positive reals such that abc=1abc=1.Prove the inequality 2a2+1ab+1a+13\sum\frac{2a^2+\frac{1}{a}}{b+\frac{1}{a}+1}\geq 3