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Regional Olympiad - FBH 2013 Grade 9 Problem 2

Source: Regional Olympiad - Federation of Bosnia and Herzegovina 2013

September 24, 2018
geometrycircumcircleantipode

Problem Statement

In triangle ABCABC, ∠ACB=50∘\angle ACB=50^{\circ} and ∠CBA=70∘\angle CBA=70^{\circ}. Let DD be a foot of perpendicular from point AA to side BCBC, OO circumcenter of ABCABC and EE antipode of AA in circumcircle ABCABC. Find ∠DAE\angle DAE
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