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siilk road geometry 2016

Source: SRMC 2016

August 31, 2018
geometryequal anglescircumcircle

Problem Statement

Around the acute-angled triangle ABCABC (AC>CBAC>CB) a circle is circumscribed, and the point NN is midpoint of the arc ACBACB of this circle. Let the points A1A_1 and B1B_1 be the feet of perpendiculars on the straight line NCNC, drawn from points AA and BB respectively (segment NCNC lies inside the segment A1B1A_1B_1). Altitude A1A2A_1A_2 of triangle A1ACA_1AC and altitude B1B2B_1B_2 of triangle B1BCB_1BC intersect at a point KK . Prove that A1KN=B1KM\angle A_1KN=\angle B_1KM, where MM is midpoint of the segment A2B2A_2B_2 .